GCSE Maths · Geometry and measures

Circle Theorems Exam Questions and Worked Answers

Circle theorems are exact angle and length relationships created by radii, chords, tangents and points on a circle. In an exam, identify the matching relationship, calculate with ordinary angle facts and state the theorem as your reason.

Edexcel · AQA · OCRHigher tier15 original questions
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Read the objects before recalling rules

What you need to know about circle theorems

A circle has a centre and a curved boundary called the circumference. A radius joins the centre to the circumference. A chord joins two points on the circumference. A tangent is a straight line that touches the circle at exactly one point. Circle theorems describe relationships made by these concrete objects.

Picture → relationship → angle reason

Name the lines in the diagram first

The same line segment can play a different role depending on its endpoints. Find the centre and touching point before choosing an angle fact.

Radiuscentre → circumferenceall radii in one circle are equal
Chordcircumference → circumferencea diameter is a chord through the centre
Tangentone touching pointit is perpendicular to the radius there
Radius, chord and tangentA labelled circle diagram illustrating radius, chord and tangent. The drawing is not to scale. ABTOradiuschordtangentDiagram not drawn accurately
Radius, chord and tangent. Use the labelled relationships, not visual measurement.
From problem to method

Typical problems you need to be able to solve

These are the main kinds of question in this topic. Each card first states the problem, then explains how to solve it.

Use the centre–circumference relationship

What the problem asks: Find one angle when the same arc forms an angle at the centre and an angle at the circumference.

How to solve it: The centre angle is twice the circumference angle on the same arc.

AOC=2ABC\angle AOC=2\angle ABC

Use a diameter

What the problem asks: Find an angle in a triangle whose base is a diameter and whose third vertex lies on the circumference.

How to solve it: The angle subtended by a diameter at the circumference is 90°.

ABC=90\angle ABC=90^\circ

Use the same segment

What the problem asks: Compare two angles at the circumference that stand on the same chord and lie in the same segment.

How to solve it: Angles subtended by the same chord in the same segment are equal.

ABC=ADC\angle ABC=\angle ADC

Use a cyclic quadrilateral

What the problem asks: Find an angle in a four-sided shape whose four vertices lie on the circumference.

How to solve it: Opposite angles in a cyclic quadrilateral add to 180°.

ABC+ADC=180\angle ABC+\angle ADC=180^\circ

Use a tangent

What the problem asks: Relate a tangent to a radius, chord or another tangent.

How to solve it: A tangent is perpendicular to the radius at contact; tangent lengths from one external point are equal; the tangent–chord angle equals the angle in the alternate segment.

OT tangent,PA=PBOT\perp\text{ tangent},\qquad PA=PB

Use a chord and the centre

What the problem asks: Find a chord length or prove two chord pieces are equal when a perpendicular from the centre is shown.

How to solve it: A perpendicular from the centre to a chord bisects the chord, creating two equal lengths and right-angled triangles.

OMABAM=MBOM\perp AB\quad\Rightarrow\quad AM=MB

A reliable routine

Method for multi-step circle theorem questions

Use this routine when a diagram combines one or more circle theorems with triangle, straight-line or isosceles-angle facts. It works by turning each known relationship into one justified local step.

  1. Mark the centre, radii, chords, diameter, tangent and any four points on the circumference.
  2. Write the circle theorem that directly connects the given angle or length to the unknown region.
  3. Calculate one new fact at a time, also using equal radii, angles in a triangle or angles on a straight line when needed.
  4. Write a reason beside every important angle statement.
  5. Check that triangle totals are 180° and that the final angle size fits its position in the diagram.

Check: Do not write only ‘circle theorem’. Name the relationship, for example ‘opposite angles in a cyclic quadrilateral sum to 180°’.

Fully worked

Circle theorems GCSE worked examples

Each solution explains the clue, why the method fits and how to check the result.

Example 1

Angle at the centre

2 marks
Question

Angle AOC=116AOC=116^\circ, where OO is the centre. Point BB is on the circumference on the opposite arc. Find angle ABCABC.

Angle at the centre and circumferenceA labelled circle diagram illustrating angle at the centre and circumference. The drawing is not to scale.ABCODiagram not drawn accurately
Angle at the centre and circumference. Use the labelled relationships, not visual measurement.

The centre angle is twice the circumference angle on the same arc.

ABC=116÷2\angle ABC=116^\circ\div2

ABC=58\boxed{\angle ABC=58^\circ}

Example 2

Angle in a semicircle

2 marks
Question

ACAC is a diameter and BB is on the circumference. Find angle ABCABC.

Angle in a semicircleA labelled circle diagram illustrating angle in a semicircle. The drawing is not to scale.ABCDiagram not drawn accurately
Angle in a semicircle. Use the labelled relationships, not visual measurement.

A diameter subtends a right angle at the circumference.

ABC=90\boxed{\angle ABC=90^\circ}

Example 3

Angles in the same segment

2 marks
Question

Angles ABCABC and ADCADC stand on the same chord ACAC in the same segment. If ABC=43\angle ABC=43^\circ, find ADC\angle ADC.

Angles standing on chord AC in the same segmentA labelled circle diagram illustrating angles standing on chord ac in the same segment. The drawing is not to scale.ABCDDiagram not drawn accurately
Angles standing on chord AC in the same segment. Use the labelled relationships, not visual measurement.

Angles in the same segment are equal.

ADC=43\boxed{\angle ADC=43^\circ}

Example 4

Opposite cyclic angles

2 marks
Question

ABCDABCD is a cyclic quadrilateral. Angle ABC=112ABC=112^\circ. Find angle ADCADC.

Cyclic quadrilateralA labelled circle diagram illustrating cyclic quadrilateral. The drawing is not to scale.ABCDDiagram not drawn accurately
Cyclic quadrilateral. Use the labelled relationships, not visual measurement.

Opposite angles in a cyclic quadrilateral sum to 180180^\circ.

ADC=180112\angle ADC=180^\circ-112^\circ

ADC=68\boxed{\angle ADC=68^\circ}

Example 5

Radius and tangent

3 marks
Question

A tangent touches a circle at TT, and OTOT is a radius. A line through OO makes an angle of 3434^\circ with OTOT. Find its acute angle with the tangent.

Radius perpendicular to a tangentA labelled circle diagram illustrating radius perpendicular to a tangent. The drawing is not to scale.TODiagram not drawn accurately
Radius perpendicular to a tangent. Use the labelled relationships, not visual measurement.

The radius and tangent meet at 9090^\circ.

9034=5690^\circ-34^\circ=\boxed{56^\circ}

Example 6

Alternate segment theorem

2 marks
Question

The angle between a tangent at AA and chord ABAB is 5151^\circ. Point CC lies on the opposite arc. Find angle ACBACB.

Tangent and alternate segmentA labelled circle diagram illustrating tangent and alternate segment. The drawing is not to scale.ABCDiagram not drawn accurately
Tangent and alternate segment. Use the labelled relationships, not visual measurement.

The angle between a tangent and chord equals the angle in the alternate segment subtended by that chord.

ACB=51\boxed{\angle ACB=51^\circ}

Example 7

Perpendicular from the centre to a chord

4 marks
Question

A circle has radius 1313 cm. The perpendicular distance from its centre to chord ABAB is 55 cm. Find the length of ABAB.

Perpendicular from the centre to a chordA labelled circle diagram illustrating perpendicular from the centre to a chord. The drawing is not to scale.ABODiagram not drawn accurately
Perpendicular from the centre to a chord. Use the labelled relationships, not visual measurement.

The perpendicular from the centre bisects the chord. Let MM be the midpoint of ABAB.

In right-angled triangle OMAOMA,

AM2+52=132AM^2+5^2=13^2

AM2=16925=144AM^2=169-25=144

AM=12AM=12

Therefore

AB=2(12)=24 cmAB=2(12)=\boxed{24\text{ cm}}

Example 8

Prove the centre-angle theorem

4 marks
Question

Points AA, BB and CC lie on a circle with centre OO. Prove that the angle at the centre standing on arc ACAC is twice ABC\angle ABC.

Construction for the centre-angle proofA labelled circle diagram illustrating construction for the centre-angle proof. The drawing is not to scale.ABCODiagram not drawn accurately
Construction for the centre-angle proof. Use the labelled relationships, not visual measurement.

Join OO to BB. Let ABO=x\angle ABO=x and OBC=y\angle OBC=y.

Because OA=OBOA=OB, triangle AOBAOB is isosceles.

AOB=1802x\angle AOB=180^\circ-2x

Because OB=OCOB=OC, triangle BOCBOC is isosceles.

BOC=1802y\angle BOC=180^\circ-2y

Angles around OO total 360360^\circ, so the remaining angle standing on arc ACAC is

360(1802x)(1802y)=2x+2y360^\circ-(180^\circ-2x)-(180^\circ-2y)=2x+2y

But ABC=x+y\angle ABC=x+y. Therefore

AOC=2ABC\boxed{\angle AOC=2\angle ABC}

15 original questions · total 45 marks

Circle theorems GCSE exam-style questions

Try each question before opening its fully worked answer. The difficulty rises through the set.

Before you startAllow about 55 minutes · write a named angle reason for every theorem step and do not measure the diagrams · answers start collapsed
1

Halve a centre angle

2 marks

An angle at the centre is 146146^\circ. Find the angle at the circumference on the same arc.

Show worked answer

146÷2=73146^\circ\div2=\boxed{73^\circ}

The centre angle is twice the circumference angle.

2

Double a circumference angle

2 marks

An angle at the circumference is 3737^\circ. Find the angle at the centre on the same arc.

Show worked answer

2(37)=742(37^\circ)=\boxed{74^\circ}

3

Use a semicircle with a triangle

3 marks

ACAC is a diameter. Point BB lies on the circumference and BAC=28\angle BAC=28^\circ. Find BCA\angle BCA.

Triangle drawn on diameter ACA labelled circle diagram illustrating triangle drawn on diameter ac. The drawing is not to scale.ABCDiagram not drawn accurately
Triangle drawn on diameter AC. Use the labelled relationships, not visual measurement.
Show worked answer

ABC=90\angle ABC=90^\circ

because the angle in a semicircle is a right angle.

BCA=1809028\angle BCA=180^\circ-90^\circ-28^\circ

BCA=62\boxed{\angle BCA=62^\circ}

4

Use the same chord

2 marks

Angles ABCABC and ADCADC lie in the same segment and stand on chord ACAC. If ABC=67\angle ABC=67^\circ, find ADC\angle ADC.

Two angles standing on chord ACA labelled circle diagram illustrating two angles standing on chord ac. The drawing is not to scale.ABCDDiagram not drawn accurately
Two angles standing on chord AC. Use the labelled relationships, not visual measurement.
Show worked answer

Angles in the same segment are equal.

ADC=67\boxed{\angle ADC=67^\circ}

5

Find an opposite cyclic angle

2 marks

ABCDABCD is cyclic and ABC=97\angle ABC=97^\circ. Find ADC\angle ADC.

Cyclic quadrilateral ABCDA labelled circle diagram illustrating cyclic quadrilateral abcd. The drawing is not to scale.ABCDDiagram not drawn accurately
Cyclic quadrilateral ABCD. Use the labelled relationships, not visual measurement.
Show worked answer

ADC=18097\angle ADC=180^\circ-97^\circ

ADC=83\boxed{\angle ADC=83^\circ}

6

Form and solve a cyclic equation

4 marks

Opposite angles of a cyclic quadrilateral are (3x+8)(3x+8)^\circ and (5x4)(5x-4)^\circ. Find xx.

Show worked answer

Opposite cyclic angles sum to 180180^\circ.

3x+8+5x4=1803x+8+5x-4=180

8x+4=1808x+4=180

8x=1768x=176

x=22\boxed{x=22}

7

Use a tangent and radius

2 marks

A radius meets a tangent at TT. Find the angle between them.

Radius OT meeting a tangent at TA labelled circle diagram illustrating radius ot meeting a tangent at t. The drawing is not to scale.TODiagram not drawn accurately
Radius OT meeting a tangent at T. Use the labelled relationships, not visual measurement.
Show worked answer

A tangent is perpendicular to the radius at the point of contact.

90\boxed{90^\circ}

8

Use equal tangents

2 marks

Tangents PAPA and PBPB are drawn from the same external point PP. If PA=7.6PA=7.6 cm, find PBPB.

Two tangents from external point PA labelled circle diagram illustrating two tangents from external point p. The drawing is not to scale.ABPDiagram not drawn accurately
Two tangents from external point P. Use the labelled relationships, not visual measurement.
Show worked answer

Tangents from the same external point are equal in length.

PB=7.6 cm\boxed{PB=7.6\text{ cm}}

9

Use the alternate segment

2 marks

The angle between tangent ATAT and chord ABAB is 3939^\circ. Find the angle subtended by chord ABAB at the opposite circumference.

Tangent, chord and alternate-segment angleA labelled circle diagram illustrating tangent, chord and alternate-segment angle. The drawing is not to scale.ABCDiagram not drawn accurately
Tangent, chord and alternate-segment angle. Use the labelled relationships, not visual measurement.
Show worked answer

By the alternate segment theorem, the two angles are equal.

39\boxed{39^\circ}

10

Find a chord length

4 marks

A circle has radius 1010 cm. The perpendicular distance from the centre to a chord is 66 cm. Find the chord length.

Show worked answer

The perpendicular bisects the chord. For half the chord,

h2+62=102h^2+6^2=10^2

h2=64h^2=64

h=8h=8

chord=2h=16 cm\text{chord}=2h=\boxed{16\text{ cm}}

11

Use equal radii

3 marks

OO is the centre and A,BA,B lie on the circle. Angle AOB=104AOB=104^\circ. Find angle OABOAB.

Show worked answer

Triangle AOBAOB is isosceles because OA=OBOA=OB.

OAB=1801042\angle OAB=\frac{180^\circ-104^\circ}{2}

OAB=38\boxed{\angle OAB=38^\circ}

12

Combine two circle facts

4 marks

ACAC is a diameter and DD lies on the circumference. A tangent at AA makes an angle of 3232^\circ with chord ADAD. Find angles ACDACD and ADCADC.

Diameter AC, tangent at A and chord ADA labelled circle diagram illustrating diameter ac, tangent at a and chord ad. The drawing is not to scale.ADCDiagram not drawn accurately
Diameter AC, tangent at A and chord AD. Use the labelled relationships, not visual measurement.
Show worked answer

By the alternate segment theorem,

ACD=32\angle ACD=32^\circ

Because ACAC is a diameter,

ADC=90\angle ADC=90^\circ

ACD=32,ADC=90\boxed{\angle ACD=32^\circ,\quad \angle ADC=90^\circ}

13

Explain a theorem

3 marks

Explain why the angle subtended by a diameter at the circumference is 9090^\circ.

Show worked answer

The diameter forms an angle of 180180^\circ at the centre.

The angle at the centre is twice the angle at the circumference on the same arc.

180÷2=90180^\circ\div2=90^\circ

Therefore an angle in a semicircle is 90\boxed{90^\circ}.

14

Prove angles in the same segment are equal

4 marks

Angles ABCABC and ADCADC stand on the same chord ACAC. Use the centre-angle theorem to prove that they are equal.

Two circumference angles standing on chord ACA labelled circle diagram illustrating two circumference angles standing on chord ac. The drawing is not to scale.ABCDDiagram not drawn accurately
Two circumference angles standing on chord AC. Use the labelled relationships, not visual measurement.
Show worked answer

Both circumference angles stand on the same chord ACAC and the same centre angle AOCAOC.

By the centre-angle theorem,

AOC=2ABC\angle AOC=2\angle ABC

and

AOC=2ADC\angle AOC=2\angle ADC

Therefore

2ABC=2ADC2\angle ABC=2\angle ADC

ABC=ADC\boxed{\angle ABC=\angle ADC}

15

Solve a multi-step tangent problem

6 marks

OO is the centre of a circle. AA and BB lie on the circumference, and AOB=140\angle AOB=140^\circ. A tangent is drawn at AA.

(a) Find OAB\angle OAB.

(b) Find the acute angle between the tangent and chord ABAB.

(c) State the angle subtended by chord ABAB at the opposite circumference.

Radius, chord and tangent for a multi-step problemA labelled circle diagram illustrating radius, chord and tangent for a multi-step problem. The drawing is not to scale.ABODiagram not drawn accurately
Radius, chord and tangent for a multi-step problem. Use the labelled relationships, not visual measurement.
Show worked answer

Triangle AOBAOB is isosceles because OA=OBOA=OB.

OAB=1801402=20\angle OAB=\frac{180^\circ-140^\circ}{2}=20^\circ

The radius OAOA is perpendicular to the tangent.

tangent–chord angle=9020=70\text{tangent--chord angle}=90^\circ-20^\circ=70^\circ

By the alternate segment theorem, the angle subtended by ABAB at the opposite circumference is also 7070^\circ.

20, 70, 70\boxed{20^\circ,\ 70^\circ,\ 70^\circ}

Examiner-style feedback

Common circle theorems mistakes

Using the visible shape instead of the labels

Circle theorem diagrams are often not drawn accurately. Use centres, equal radii, chords and tangent marks.

Applying a rule to different arcs

Centre and circumference angles must stand on the same arc; same-segment angles must stand on the same chord.

Forgetting ordinary angle facts

Many questions also need equal base angles, a 180° triangle total or a straight-line angle.

Giving no reason

Write the full theorem relationship. An unsupported angle may lose a reasoning mark.

Using the wrong centre angle

Check whether the circumference angle stands on the minor or major arc. The matching centre angle may be reflex, so compare the endpoints of both angles.

Matching the wrong alternate-segment angle

Use the angle between the tangent and the named chord, then match the circumference angle standing on that same chord.

30-second recap

Choose, carry out, check

Translate the wording before you reach for a rule.

  1. Name the circle objects first.
  2. Match the given and unknown to one theorem.
  3. Use one justified angle step at a time.
  4. State the exact theorem and check ordinary angle totals.
Quick answers

Circle theorems FAQ

How many circle theorems do I need for GCSE?

Courses commonly group the required relationships into seven families covering centre and circumference angles, semicircles, same segments, cyclic quadrilaterals, tangents and chords.

Are circle theorem diagrams drawn to scale?

Do not assume so. Use the labels and theorem conditions rather than measuring or judging the picture.

What does subtended mean?

An arc or chord subtends an angle when lines from its two endpoints meet at the angle’s vertex.

How do I earn proof marks?

State each new angle or equality and give its precise reason, including ordinary triangle and straight-line facts.

Build connected skills

What to revise next

Content standards

Curriculum and rights review

Reviewed 5 September 2026 against DfE content G10, Pearson Edexcel G10, AQA G10 and OCR J560 sections 8.05b–h. All questions, proofs and diagrams are original.