Surface area is the total area of the exposed outside of a solid. List each face or curved surface, calculate its area and add once; exclude missing or joined faces.
Foundation & Higher6 worked examples10 original questions
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Start with the meaning
What you need to know about surface area
To wrap a box exactly, with no overlap, imagine covering every outside face with paper. The total paper needed is its surface area. This measures the outside covering, not the space inside the box, and is measured in square units such as cm².
See the idea first
Unfold the faces so none is missed
A net is a flat arrangement of the faces that can fold into the solid. A cube has six equal square faces, so a cube with side a has surface area 6a². A cuboid has three pairs of equal rectangles instead.
A cube has six square faces. This net shows all six without overlap, including faces hidden in a perspective drawing.
From problem to method
Typical problems you need to be able to solve
These are the main kinds of question in this topic. Each card first states the problem, then explains how to solve it.
Find a closed box's surface area
What the problem asks: A cuboid measures 5 cm by 3 cm by 2 cm. Find its total surface area.
How to solve it: Face areas are 15, 10 and 6 cm², with two of each. Add 2 × (15 + 10 + 6) = 62 cm².
Leave out a missing face
What the problem asks: The same box has no lid. Find the area of material.
How to solve it: The missing 5 cm by 3 cm lid has area 15 cm². Subtract it from the closed-box total: 62 − 15 = 47 cm².
Include a curved surface
What the problem asks: Find the surface area of a closed cylinder with radius 3 cm and height 5 cm.
How to solve it: The curved side unrolls into a rectangle of width 2πr and height h: 30π cm². Add two circular ends, 18π cm², giving 48π cm².
A reliable routine
Add the surfaces that are actually exposed
This works when a solid's boundary can be separated into non-overlapping faces or known curved surfaces. A net makes the counting visible. For joined solids, a touching face is inside, not part of the exposed boundary.
List faces, including hidden ones, and mark any missing or joined faces.
Calculate the area of each different face and its number of copies.
For a cylinder, use curved area 2πrh; for a cone, curved area πrl with slant height l.
Add only the required surfaces and state square units. A sphere uses its own formula, 4πr².
Check: Cone slant height follows the sloping surface, while perpendicular height goes straight from apex to base. They are different lengths.
Fully worked
Surface area GCSE worked examples
Each solution explains the clue, why the method fits and how to check the result.
Example 1
Cube
2 marks
Question
Find the surface area of a cube of side 5 cm.
One square face has area 52=25 cm².
S=6(25)=150 cm2
All six faces count.
Example 2
Cuboid
3 marks
Question
Find the surface area of a closed cuboid measuring 7 cm by 4 cm by 3 cm.
The three face pairs have areas 28, 21 and 12 cm² per face.
S=2(28+21+12)=2(61)=122 cm2
Tip: counting only visible faces misses the opposite ones.
Example 3
Open box
3 marks
Question
A thin-walled rectangular box is 8 cm long, 5 cm wide and 4 cm high, with no lid. Find its material area, ignoring thickness.
Base: 8(5)=40. Two long walls: 2(8)(4)=64. Two short walls: 2(5)(4)=40.
S=40+64+40=144 cm2
There is no top face.
Example 4
Closed cylinder
3 marks
Question
A closed cylinder has radius 3 cm and height 5 cm. Find its total surface area in terms of π.
Unroll the curved surface into a rectangle. Its width is the distance around the circular rim, 2πr. Add two circles for a closed cylinder.
Curved side: 2π(3)(5)=30π. Two ends: 2π(3)2=18π.
S=30π+18π=48π cm2
The net explains both contributions.
Example 5
Cone with its base
3 marks
Question
A cone has radius 4 cm and slant height 9 cm. Use curved area πrl to find its total surface area, including the base.
Scurved=π(4)(9)=36πSbase=π(4)2=16πS=52π cm2
The given 9 cm is slant height, which belongs in the curved-area formula.
Example 6
Joined cubes
Harder4 marks
Question
Two cubes, each of side 3 cm, are joined along one complete face. Find the exposed surface area.
Separate cubes have 2×6×32=108 cm² of surface. The two faces at the join are now internal; each is 9 cm².
S=108−2(9)=90 cm2
Remove both touching faces, not just one.
10 original questions · total 28 marks
Surface area GCSE exam-style questions
Try each question before opening its fully worked answer. The difficulty rises through the set.
Before you startAllow about 33 minutes · Show your working. Give exact answers unless a question asks you to round, and include units where needed. · answers start collapsed
1
Cube
2 marks
Find the total surface area of a cube of side 4 cm.
Show worked answer
S=6(42)=6(16)=96 cm2
2
Cuboid
3 marks
Find the surface area of a 6 cm by 5 cm by 2 cm closed cuboid.
Show worked answer
S=2(6⋅5+6⋅2+5⋅2)=2(30+12+10)=104 cm2
3
No lid
3 marks
A cube-shaped box of side 6 cm has no lid. Ignore material thickness. Find material area.
Show worked answer
Five square faces remain.
S=5(62)=180 cm2
4
Cylinder's curved side
2 marks
Find only the curved surface area of a cylinder with radius 2 cm and height 7 cm.
Show worked answer
S=2πrh=2π(2)(7)=28π cm2
Do not add the ends when only the curved side is requested.
5
Closed cylinder
3 marks
A closed cylinder has diameter 10 cm and height 6 cm. Find total surface area in terms of π.
Show worked answer
Radius is 5 cm.
S=2π(5)(6)+2π(5)2=60π+50π=110π cm2
6
Sphere
2 marks
Find a sphere's surface area for radius 7 cm, using S=4πr2.
Show worked answer
S=4π(7)2=196π cm2
7
Closed hemisphere
3 marks
A hemisphere has radius 3 cm. Use sphere surface area 4πr2 to find its total surface area, including the flat base.
G17 surface area across tiers, with formulas given for less familiar curved solids and harder composite examples labelled locally. Questions, suggested marks, solutions and diagrams are original practice material, not official past-paper questions.