GCSE Maths · Statistics

Frequency tables GCSE Questions and Worked Answers

Frequency tells you how often a value or category occurs. Add frequencies to count observations; multiply value by frequency to recover a numerical total. Grouped data usually gives estimates rather than exact individual values.

Foundation & Higher6 worked examples10 original questions
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Start with the meaning

What you need to know about frequency tables

Suppose players score 0, 0, 1, 1, 1, 2, 2, 2, 2 and 3 goals. Rather than repeat every number, record that zero occurs twice, one three times, two four times and three once. These occurrence counts are called frequencies.

See the idea first

A row represents repeated observations

In the table, x means the number of goals and f the number of players with that score. Four players scoring two goals contribute 2 × 4 = 8 goals. Add the frequency column to count people; add the x × f column to count goals.

Goals scored by ten players
Goals xPlayers fTotal goals x × f
020
133
248
313
From problem to method

Typical problems you need to be able to solve

These are the main kinds of question in this topic. Each card first states the problem, then explains how to solve it.

Find a total and mean

What the problem asks: Use the goals table to find the number of players and mean goals.

How to solve it: There are 2 + 3 + 4 + 1 = 10 players. Goals total 0 + 3 + 8 + 3 = 14. Mean = 14 ÷ 10 = 1.4.

Find the median

What the problem asks: Use the same table to find the median number of goals.

How to solve it: Ten players give middle positions 5 and 6. Positions 3–5 score 1, while positions 6–9 score 2. Median = (1 + 2) ÷ 2 = 1.5.

Estimate from groups

What the problem asks: Times are grouped as 0 < t ≤ 10, 10 < t ≤ 20 and 20 < t ≤ 30 seconds. How can a mean be estimated?

How to solve it: Use each interval's midpoint as a representative value: 5, 15 and 25. Multiply midpoint by frequency, add and divide by total frequency. Exact times have been lost, so this is an estimate.

A reliable routine

Recover a mean from repeated values

For a numerical frequency table, x × f reconstructs the total contribution of a row because it replaces adding x repeatedly. The compact notation Σ means ‘add all rows’: mean = Σfx ÷ Σf.

  1. Read value and frequency headings; count total frequency.
  2. Multiply each numerical value by its frequency. For grouped data, first use class midpoints.
  3. Add these products and divide by the total frequency, not the number of rows.
  4. For median instead, accumulate frequencies until you locate the middle position or positions.

Check: A class such as 10 < t ≤ 20 includes 20 but excludes 10. A categorical label such as colour has no meaningful numerical mean.

Fully worked

Frequency tables GCSE worked examples

Each solution explains the clue, why the method fits and how to check the result.

Example 1

Make a frequency table

2 marks
Question

Summarise the scores 1, 3, 1, 2, 3, 3, 2, 1 in a frequency table.

Count once per observation: score 1 occurs 3 times; score 2 occurs 2 times; score 3 occurs 3 times. Check total frequency: 3 + 2 + 3 = 8.

Score counts
ScoreFrequency
13
22
33
Example 2

Mean from frequencies

3 marks
Question

Find the mean number of goals from this table.

Goals scored by ten players
Goals xPlayers fTotal goals x × f
020
133
248
313

Total frequency is 2+3+4+1=102+3+4+1=10.

Total goals=0(2)+1(3)+2(4)+3(1)=14\text{Total goals}=0(2)+1(3)+2(4)+3(1)=14 Mean=14/10=1.4\text{Mean}=14/10=1.4

The zero-goal players still count in the denominator.

Example 3

Median and mode

3 marks
Question

Find the median and mode of the goals table.

Goals scored by ten players
Goals xPlayers fTotal goals x × f
020
133
248
313

The cumulative counts are 2, 5, 9, 10. Position 5 has value 1 and position 6 value 2.

Median=(1+2)/2=1.5\text{Median}=(1+2)/2=1.5

The greatest frequency is 4, corresponding to 2 goals, so the mode is 2, not 4.

Example 4

Grouped mean estimate

4 marks
Question

Estimate the mean time using this grouped table.

Times taken by 20 runners
Time t (s)Frequency
0 < t ≤ 104
10 < t ≤ 2010
20 < t ≤ 306

Midpoints are 5, 15 and 25 s.

Estimated total=5(4)+15(10)+25(6)\text{Estimated total}=5(4)+15(10)+25(6) =20+150+150=320 s=20+150+150=320\text{ s} Estimated mean=320/20=16 s\text{Estimated mean}=320/20=16\text{ s}

We do not know individual times, so the mean is not exact.

Example 5

Median class

2 marks
Question

Identify the class containing the median in the grouped times table.

Times taken by 20 runners
Time t (s)Frequency
0 < t ≤ 104
10 < t ≤ 2010
20 < t ≤ 306

There are 20 times, so middle positions are 10 and 11. Cumulative frequencies are 4, 14, 20: both positions lie in 10 < t ≤ 20 seconds. The exact median cannot be recovered from these groups alone.

Example 6

Missing frequency

Harder4 marks
Question

Scores 1, 2 and 3 have frequencies 2, k and 4. Their mean is 2.2. Find k.

Total frequency is k + 6; total score is 2k + 14.

2k+14k+6=2.2\frac{2k+14}{k+6}=2.2 2k+14=2.2k+13.22k+14=2.2k+13.2 0.8=0.2k0.8=0.2k k=4k=4

Check: total 22 divided by 10 observations is 2.2.

10 original questions · total 20 marks

Frequency tables GCSE exam-style questions

Try each question before opening its fully worked answer. The difficulty rises through the set.

Before you startAllow about 25 minutes · Show your working. Give exact answers unless a question asks you to round, and include units where needed. · answers start collapsed
1

Read a row

1 mark

A table records ‘2 pets, frequency 6’. How many pets do those six households have in total?

Show worked answer

Six households each have two pets:

2(6)=12 pets2(6)=12\text{ pets}
2

Count observations

1 mark

Frequencies are 3, 7, 5 and 2. Find the total number of observations.

Show worked answer
3+7+5+2=173+7+5+2=17

Add frequencies, not category labels.

3

Mean

3 marks

Values 1, 2 and 4 have frequencies 2, 5 and 3. Find the mean.

Show worked answer
T=1(2)+2(5)+4(3)=24T=1(2)+2(5)+4(3)=24 N=2+5+3=10N=2+5+3=10 Mean=24/10=2.4\text{Mean}=24/10=2.4
4

Mode

1 mark

Scores 0, 1, 2 and 3 have frequencies 2, 8, 5 and 1. Find the mode.

Show worked answer

The greatest frequency is 8, which belongs to score 1. The mode is the score, not its frequency.

5

Median position

3 marks

Values 2, 5 and 7 have frequencies 3, 4 and 2. Find the median.

Show worked answer

There are nine observations, so locate position 5. The first three values are 2, positions 4–7 are 5, and the last two are 7. Median = 5.

6

Class boundaries

2 marks

Which class contains 20: 10 < x ≤ 20 or 20 < x ≤ 30? Explain.

Show worked answer

The first class includes 20 through ≤. The second excludes 20 through <. Each observation belongs in exactly one class.

7

Grouped estimate

3 marks

Classes 0 < x ≤ 10 and 10 < x ≤ 20 have frequencies 3 and 7. Estimate the mean.

Show worked answer

Midpoints are 5 and 15.

xˉ5(3)+15(7)3+7\bar x\approx\frac{5(3)+15(7)}{3+7} =12010=12=\frac{120}{10}=12

It is an estimate because actual values within each class are unknown.

8

Modal class

1 mark

The equal-width classes 0 < t ≤ 5, 5 < t ≤ 10 and 10 < t ≤ 15 have frequencies 4, 9 and 6. Find the modal class.

Show worked answer

The greatest frequency is 9, so the modal class is 5 < t ≤ 10, not the number 9.

9

A category mean?

2 marks

A table counts red, green and blue cars. Can it give a meaningful mean colour? Explain.

Show worked answer

No. Colour categories are not numerical measurements. You can find the most frequent colour, the mode, or each colour's proportion.

10

Combine counts

3 marks

One class records 5 pupils with 0 siblings and 15 with 1 sibling. Another records 3 with 0 and 7 with 1. Find the combined mean number of siblings.

Show worked answer

Combined frequencies: zero has 8, one has 22. There are 30 pupils and 22 siblings counted.

Mean=2230=1115\text{Mean}=\frac{22}{30}=\frac{11}{15}

This is about 0.733 siblings per pupil.

Examiner-style feedback

Common frequency tables mistakes

Dividing by rows

The observations are counted by total frequency, not by the number of distinct values.

Mode confused with frequency

Report the value or category whose frequency is largest.

Calling a grouped mean exact

Midpoints represent unknown values; state that the result is an estimate.

30-second recap

Choose, carry out, check

Translate the wording before you reach for a rule.

  1. Read what each column counts.
  2. Multiply values by their frequencies.
  3. Divide a total by the observation count.
  4. Treat grouped values as estimates.
Quick answers

Frequency tables FAQ

What does Σ mean?

It means add all the entries indicated. Σf is total frequency; Σfx is the sum of value × frequency products.

Can I always find an exact grouped median?

No. Groups locate a median class, but do not reveal the individual middle observations.

Build connected skills

What to revise next

Content standards

Curriculum and rights review

S2/S4 numerical and categorical frequency tables, grouped estimates and median classes across tiers. Questions, suggested marks, solutions and diagrams are original practice material, not official past-paper questions.

Official specification references