GCSE Maths · Geometry and measures

Cosine Rule GCSE Questions, Worked Examples and Answers

The cosine rule connects all three sides of any triangle with one angle. Use it to find a side from two sides and their included angle, or to find an angle when all three sides are known.

Edexcel · AQA · OCRHigher tierOriginal diagrams · 10 questions
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Match each angle with its opposite side

What you need to know about the cosine rule

In a triangle, every angle faces one side. We name an angle with a capital letter and its opposite side with the matching lower-case letter. The cosine rule uses this pairing, so identifying the opposite pair comes before substituting any numbers.

Two sides + included angle

Read the triangle before the formula

To find side a, the known angle must be A and the two sides meeting at A are b and c.

Targetside aopposite angle A
Knownsides b, c and angle Athe included angle sits between b and c
Relationshipa² = b² + c² − 2bc cos Athen take the positive square root
Triangle labelled for the cosine ruleAngle A is at the left vertex. Side a is opposite angle A, while sides b and c meet at angle A.ABCAabc
Lower-case side a is opposite upper-case angle A. This matching pair determines which term appears alone in the cosine rule.
From problem to method

Typical problems you need to be able to solve

These are the main kinds of question in this topic. Each card first states the problem, then explains how to solve it.

Find a missing side

What the problem asks: Two side lengths and the angle between them are known.

How to solve it: Match the missing side with its opposite angle, substitute into a² = b² + c² − 2bc cos A, then take the positive square root.

Find a missing angle

What the problem asks: All three side lengths are known.

How to solve it: Rearrange to cos A = (b² + c² − a²) ÷ 2bc, then use inverse cosine in degree mode.

Solve a contextual distance

What the problem asks: Two journeys, bearings or forces form two known sides with an included angle.

How to solve it: Draw the triangle, calculate the included angle carefully, then use the missing-side form.

Complete a multi-step shape

What the problem asks: A diagonal divides a compound shape into triangles.

How to solve it: Use the cosine rule in the triangle with sufficient information, then carry the result into the next valid relationship.

A reliable routine

Method for a cosine-rule calculation

Use the rule for SAS data when finding a side, or SSS data when finding an angle. It works for any triangle and extends Pythagoras by accounting for the included angle.

  1. Sketch or mark the target side or angle.
  2. Label the target pair with matching lower-case and capital letters.
  3. Choose the side form or rearranged angle form.
  4. Substitute with brackets and check the calculator is in degree mode.
  5. Keep the full calculator value until the final requested accuracy.

Check: If A = 90°, cos A = 0, so the final term disappears and the cosine rule becomes Pythagoras’ theorem.

Fully worked

Cosine rule GCSE worked examples

Each solution explains the clue, why the method fits and how to check the result.

Example 1

Find a side from SAS

Higher only3 marks
Question

In triangle ABCABC, b=8b=8 cm, c=11c=11 cm and A=60A=60^\circ. Find aa to 3 significant figures.

Triangle labelled for the cosine ruleAngle A is at the left vertex. Side a is opposite angle A, while sides b and c meet at angle A.ABC60°a8 cm11 cm
Lower-case side a is opposite upper-case angle A. This matching pair determines which term appears alone in the cosine rule.

Side aa is opposite the known angle.

a2=82+1122(8)(11)cos60a^2=8^2+11^2-2(8)(11)\cos60^\circ

a2=64+12188=97a^2=64+121-88=97

a=97a=\sqrt{97}

a=9.85 cm(3 s.f.)\boxed{a=9.85\text{ cm}\quad(3\text{ s.f.})}

Example 2

Find an angle from SSS

Higher only4 marks
Question

A triangle has a=10a=10 cm, b=7b=7 cm and c=12c=12 cm. Find angle AA to 1 decimal place.

Rearrange the rule for the angle opposite side aa.

cosA=b2+c2a22bc\cos A=\frac{b^2+c^2-a^2}{2bc}

cosA=72+1221022(7)(12)\cos A=\frac{7^2+12^2-10^2}{2(7)(12)}

cosA=93168\cos A=\frac{93}{168}

A=cos1(93168)A=\cos^{-1}\left(\frac{93}{168}\right)

A=56.4\boxed{A=56.4^\circ}

Example 3

Use an obtuse included angle

Higher only3 marks
Question

Two sides are 66 cm and 99 cm with included angle 120120^\circ. Find the opposite side to 3 significant figures.

Let the opposite side be aa.

a2=62+922(6)(9)cos120a^2=6^2+9^2-2(6)(9)\cos120^\circ

Because cos120=0.5\cos120^\circ=-0.5,

a2=36+81+54=171a^2=36+81+54=171

a=171a=\sqrt{171}

a=13.1 cm(3 s.f.)\boxed{a=13.1\text{ cm}\quad(3\text{ s.f.})}

Example 4

Find a distance between two routes

Higher only4 marks
Question

Two straight routes leave the same point. One is 77 km and the other is 99 km. The angle between them is 7070^\circ. Find the distance between their endpoints to 3 significant figures.

The required distance is opposite the included angle.

d2=72+922(7)(9)cos70d^2=7^2+9^2-2(7)(9)\cos70^\circ

d286.9055d^2\approx86.9055

d9.32231d\approx9.32231

9.32 km(3 s.f.)\boxed{9.32\text{ km}\quad(3\text{ s.f.})}

Example 5

Find a triangle perimeter

Higher only4 marks
Question

Two sides of a triangle are 55 cm and 88 cm and their included angle is 4545^\circ. Find the perimeter to 3 significant figures.

First find the third side aa.

a2=52+822(5)(8)cos45a^2=5^2+8^2-2(5)(8)\cos45^\circ

a5.69539a\approx5.69539

Now add all three sides.

5+8+5.69539=18.695395+8+5.69539=18.69539

18.7 cm(3 s.f.)\boxed{18.7\text{ cm}\quad(3\text{ s.f.})}

10 original questions · total 36 marks

Cosine rule GCSE exam-style questions

Try each question before opening its fully worked answer. The difficulty rises through the set.

Before you startAllow about 45 minutes · Label the opposite side–angle pair, show the substituted cosine rule and keep calculator values unrounded until the final answer. · answers start collapsed
1

Find a missing side

Higher only3 marks

Sides 55 cm and 77 cm include an angle of 6060^\circ. Find the opposite side to 3 significant figures.

Show worked answer

a2=52+722(5)(7)cos60a^2=5^2+7^2-2(5)(7)\cos60^\circ

a2=39a^2=39

a=39a=\sqrt{39}

6.24 cm\boxed{6.24\text{ cm}}

2

Connect to Pythagoras

Higher only3 marks

Sides 99 cm and 1212 cm include an angle of 9090^\circ. Use the cosine rule to find the opposite side.

Show worked answer

a2=92+1222(9)(12)cos90a^2=9^2+12^2-2(9)(12)\cos90^\circ

Since cos90=0\cos90^\circ=0,

a2=81+144=225a^2=81+144=225

a=15 cm\boxed{a=15\text{ cm}}

3

Find an angle

Higher only4 marks

A triangle has sides a=13a=13, b=8b=8 and c=11c=11. Find angle AA to 1 decimal place.

Show worked answer

cosA=82+1121322(8)(11)\cos A=\frac{8^2+11^2-13^2}{2(8)(11)}

cosA=16176\cos A=\frac{16}{176}

A=cos1(16176)A=\cos^{-1}\left(\frac{16}{176}\right)

A=84.8\boxed{A=84.8^\circ}

4

Find an obtuse angle

Higher only4 marks

A triangle has sides 55 cm, 66 cm and 99 cm. Find the angle opposite the 99 cm side to 1 decimal place.

Show worked answer

cosA=52+62922(5)(6)\cos A=\frac{5^2+6^2-9^2}{2(5)(6)}

cosA=13\cos A=-\frac13

A=cos1(13)A=\cos^{-1}\left(-\frac13\right)

A=109.5\boxed{A=109.5^\circ}

5

Use an isosceles triangle

Higher only3 marks

Two equal sides are each 1010 cm and their included angle is 4040^\circ. Find the base to 3 significant figures.

Show worked answer

a2=102+1022(10)(10)cos40a^2=10^2+10^2-2(10)(10)\cos40^\circ

a6.84040a\approx6.84040

6.84 cm\boxed{6.84\text{ cm}}

6

Find a separation

Higher only4 marks

Two boats leave a harbour on routes of 1212 km and 1515 km with an angle of 130130^\circ between them. Find their separation to 3 significant figures.

Show worked answer

d2=122+1522(12)(15)cos130d^2=12^2+15^2-2(12)(15)\cos130^\circ

d2600.403d^2\approx600.403

d24.5031d\approx24.5031

24.5 km\boxed{24.5\text{ km}}

7

Find a perimeter

Higher only4 marks

Two sides are 99 cm and 1313 cm with included angle 5050^\circ. Find the triangle perimeter to 3 significant figures.

Show worked answer

a2=92+1322(9)(13)cos50a^2=9^2+13^2-2(9)(13)\cos50^\circ

a9.97936a\approx9.97936

P=9+13+9.97936P=9+13+9.97936

P=32.0 cm(3 s.f.)\boxed{P=32.0\text{ cm}\quad(3\text{ s.f.})}

8

Choose the correct opposite pair

Higher only3 marks

In triangle PQRPQR, PQ=8PQ=8, PR=10PR=10 and angle QPR=35QPR=35^\circ. Write and evaluate an expression for QR2QR^2.

Show worked answer

QRQR is opposite the included 3535^\circ angle.

QR2=82+1022(8)(10)cos35QR^2=8^2+10^2-2(8)(10)\cos35^\circ

QR232.936\boxed{QR^2\approx32.936}

9

Explain the right-angle case

Higher only3 marks

Explain why the cosine rule becomes Pythagoras’ theorem when A=90A=90^\circ.

Show worked answer

a2=b2+c22bccos90a^2=b^2+c^2-2bc\cos90^\circ

Since cos90=0\cos90^\circ=0, the final term is zero.

a2=b2+c2a^2=b^2+c^2

This is Pythagoras’ theorem\boxed{\text{Pythagoras' theorem}}.

10

Form and solve a quadratic

Higher only5 marks

A triangle has sides xx, 77 and 1010. The angle opposite the 1010 side is 6060^\circ. Find the positive value of xx to 3 significant figures.

Show worked answer

Use 1010 as the side opposite 6060^\circ.

102=x2+722(x)(7)cos6010^2=x^2+7^2-2(x)(7)\cos60^\circ

100=x2+497x100=x^2+49-7x

x27x51=0x^2-7x-51=0

The positive quadratic-formula solution is

x=7+2532x=\frac{7+\sqrt{253}}2

x=11.5(3 s.f.)\boxed{x=11.5\quad(3\text{ s.f.})}

Examiner-style feedback

Common the cosine rule mistakes

Pairing a with the wrong angle

Side a must be opposite angle A. Relabel the triangle before choosing the formula line.

Using a non-included angle for SAS

For a missing side, the known angle must sit between the two known sides.

Forgetting inverse cosine

The rearranged expression gives cos A, not A. Apply cos⁻¹ in degree mode.

Rounding the new side too soon

A rounded diagonal can make every later step inaccurate. Store or retain the full calculator value.

30-second recap

Choose, carry out, check

Translate the wording before you reach for a rule.

  1. Match side a with opposite angle A.
  2. SAS finds a side; SSS finds an angle.
  3. Use degree mode.
  4. Round only the final result.
Quick answers

Cosine rule FAQ

When do I use the cosine rule?

Use it for two sides and their included angle when finding a side, or for all three sides when finding an angle.

What is the included angle?

It is the angle between the two known sides.

Can the cosine rule find an obtuse angle?

Yes. A negative cosine value produces an angle greater than 90° when inverse cosine is used.

How is it related to Pythagoras?

When the included angle is 90°, cos 90° = 0 and the cosine rule reduces to a² = b² + c².

Build connected skills

What to revise next

Contextual direction

Bearings

Build the included angle from three-figure bearings.

Revise bearings
Content standards

Curriculum and rights review

Reviewed 5 September 2026 against DfE content G22 and current Pearson Edexcel, AQA and OCR GCSE Mathematics specifications. All questions and diagrams are original.