GCSE Maths · Geometry and measures

Exact Trig Values GCSE Questions and Worked Answers

Exact trig values are sine, cosine and tangent ratios written without decimal rounding. At GCSE they come from the angles 0°, 30°, 45°, 60° and 90° and are used especially in non-calculator work.

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A ratio, not a rounded calculator result

What you need to know about exact trig values

Sine, cosine and tangent compare side lengths in a right-angled triangle. For certain angles those ratios can be written exactly using fractions and square roots. For example, cos 60° = 1/2 means the adjacent side is exactly half the hypotenuse.

Special triangle → side ratio

Build the values from two triangles

Split an equilateral triangle to obtain sides 1, √3 and 2; use a right-angled isosceles triangle with sides 1, 1 and √2.

Choose an angle30°, 45° or 60°mark opposite, adjacent and hypotenuse
Use a special triangle1 : √3 : 2 or 1 : 1 : √2exact side lengths
Form the ratioSOHCAHTOAsimplify without decimals
Special triangles used to derive exact trigonometric valuesA half-equilateral triangle has sides 1, square root 3 and 2 with angles 30 and 60 degrees. A right-angled isosceles triangle has sides 1, 1 and square root 2 with two 45 degree angles.2√3160°30°11√245°45°
The exact values are ratios from two familiar right-angled triangles, so they can be rebuilt rather than remembered as disconnected facts.
Exact trigonometric values for the GCSE special angles
Ratio30°45°60°90°
sin θ0012\frac1222\frac{\sqrt2}{2}32\frac{\sqrt3}{2}11
cos θ1132\frac{\sqrt3}{2}22\frac{\sqrt2}{2}12\frac1200
tan θ0033\frac{\sqrt3}{3}113\sqrt3undefined
Sine rises across the row while cosine is the same row in reverse. Tangent is sine divided by cosine, so tan 90° is undefined because cos 90° = 0.
From problem to method

Typical problems you need to be able to solve

These are the main kinds of question in this topic. Each card first states the problem, then explains how to solve it.

State an exact value

What the problem asks: Write sin, cos or tan of a special angle without a calculator.

How to solve it: Recall the table or rebuild the value from the matching special triangle.

Evaluate an exact expression

What the problem asks: Several trig values are added, multiplied or divided.

How to solve it: Replace each trig value first, then simplify the fractions and surds exactly.

Find an exact side

What the problem asks: A right-angled triangle uses a special angle and asks for an exact length.

How to solve it: Choose the correct SOHCAHTOA ratio, substitute its exact value, then rearrange without converting to a decimal.

Justify a special-triangle result

What the problem asks: Show why an exact length or trig value is true.

How to solve it: Draw the relevant special triangle, label its exact side ratio and form the required trig ratio.

A reliable routine

Method for an exact-value problem

Use this method when the angle is one of the GCSE special angles and the question asks for an exact answer or forbids a calculator. It works because the special triangles have exact side ratios.

  1. Identify the trig ratio and special angle.
  2. Write its exact value before doing any other calculation.
  3. Substitute the fraction or surd into the expression or triangle equation.
  4. Simplify using fraction and surd rules.
  5. Keep the final answer exact; do not replace it with a decimal.

Check: There is no finite value for tan 90° because tan θ = sin θ ÷ cos θ and cos 90° = 0.

Fully worked

Exact trig values GCSE worked examples

Each solution explains the clue, why the method fits and how to check the result.

Example 1

Derive sin 30°

2 marks
Question

Use the 1:3:21:\sqrt3:2 triangle to find sin30\sin30^\circ.

For the 3030^\circ angle, the opposite side is 11 and the hypotenuse is 22.

sin30=oppositehypotenuse\sin30^\circ=\frac{\text{opposite}}{\text{hypotenuse}}

sin30=12\boxed{\sin30^\circ=\frac12}

Example 2

Derive cos 45°

2 marks
Question

A right-angled isosceles triangle has shorter sides 11 and hypotenuse 2\sqrt2. Find cos45\cos45^\circ in rationalised form.

cos45=12\cos45^\circ=\frac1{\sqrt2}

Rationalise the denominator.

12×22=22\frac1{\sqrt2}\times\frac{\sqrt2}{\sqrt2}=\boxed{\frac{\sqrt2}{2}}

Example 3

Evaluate an exact expression

2 marks
Question

Find the exact value of 2sin30+cos602\sin30^\circ+\cos60^\circ.

2(12)+122\left(\frac12\right)+\frac12

=1+12=1+\frac12

32\boxed{\frac32}

Example 4

Find an exact opposite side

3 marks
Question

In a right-angled triangle, the hypotenuse is 1414 cm and an acute angle is 3030^\circ. Find the side opposite that angle exactly.

Let the opposite side be xx.

sin30=x14\sin30^\circ=\frac{x}{14}

12=x14\frac12=\frac{x}{14}

x=14×12x=14\times\frac12

x=7 cm\boxed{x=7\text{ cm}}

Example 5

Find an exact height

3 marks
Question

A right-angled triangle has adjacent side 55 cm and angle 6060^\circ. Find the opposite side exactly.

Let the opposite side be hh.

tan60=h5\tan60^\circ=\frac{h}{5}

3=h5\sqrt3=\frac{h}{5}

h=53 cm\boxed{h=5\sqrt3\text{ cm}}

10 original questions · total 20 marks

Exact trig values GCSE exam-style questions

Try each question before opening its fully worked answer. The difficulty rises through the set.

Before you startAllow about 25 minutes · Do not use rounded decimals. Write the exact value first, then simplify fractions and surds fully. · answers start collapsed
1

Recall cosine

1 mark

State the exact value of cos60\cos60^\circ.

Show worked answer

cos60=12\boxed{\cos60^\circ=\frac12}

2

Recall sine

1 mark

State the exact value of sin45\sin45^\circ.

Show worked answer

sin45=22\boxed{\sin45^\circ=\frac{\sqrt2}{2}}

3

Recall tangent

1 mark

State the exact value of tan30\tan30^\circ.

Show worked answer

tan30=33\boxed{\tan30^\circ=\frac{\sqrt3}{3}}

4

Add endpoint values

2 marks

Find the exact value of sin90+cos0\sin90^\circ+\cos0^\circ.

Show worked answer

1+1=21+1=\boxed{2}

5

Multiply an exact value

2 marks

Find the exact value of 4cos604\cos60^\circ.

Show worked answer

4×12=24\times\frac12=\boxed{2}

6

Keep a surd exact

2 marks

Find the exact value of 6sin456\sin45^\circ.

Show worked answer

6×226\times\frac{\sqrt2}{2}

32\boxed{3\sqrt2}

7

Multiply two trig values

Harder2 marks

Find the exact value of tan60cos60\tan60^\circ\cos60^\circ.

Show worked answer

3×12\sqrt3\times\frac12

32\boxed{\frac{\sqrt3}{2}}

8

Find a side using sine

3 marks

A right-angled triangle has hypotenuse 1818 cm. Find exactly the side opposite a 3030^\circ angle.

Show worked answer

sin30=x18\sin30^\circ=\frac{x}{18}

12=x18\frac12=\frac{x}{18}

x=9 cm\boxed{x=9\text{ cm}}

9

Find a hypotenuse using cosine

Harder3 marks

The side adjacent to a 4545^\circ angle is 88 cm. Find the hypotenuse exactly.

Show worked answer

cos45=8h\cos45^\circ=\frac8h

22=8h\frac{\sqrt2}{2}=\frac8h

h=162h=\frac{16}{\sqrt2}

h=82 cm\boxed{h=8\sqrt2\text{ cm}}

10

Find an equilateral-triangle height

Harder3 marks

An equilateral triangle has side length 1212 cm. Find its perpendicular height exactly.

Show worked answer

The height splits the triangle into two right-angled triangles with hypotenuse 1212 and base 66.

sin60=h12\sin60^\circ=\frac{h}{12}

32=h12\frac{\sqrt3}{2}=\frac{h}{12}

h=63 cm\boxed{h=6\sqrt3\text{ cm}}

Examiner-style feedback

Common exact trig values mistakes

Swapping the 30° and 60° values

For sine, the values grow from 1/2 at 30° to √3/2 at 60°. Cosine runs in the opposite order.

Leaving 1/√2

GCSE exact answers are normally written with a rationalised denominator: √2/2.

Using a decimal

0.707… is an approximation. If the question asks for an exact value, keep √2/2.

Writing a value for tan 90°

tan 90° is undefined because it would require division by cos 90° = 0.

30-second recap

Choose, carry out, check

Translate the wording before you reach for a rule.

  1. Exact means no rounding.
  2. Use the 1:√3:2 and 1:1:√2 triangles.
  3. Sine increases while cosine reverses.
  4. Substitute the exact ratio before simplifying.
Quick answers

Exact trig values FAQ

Which exact trig values are needed at GCSE?

The standard set uses sine and cosine at 0°, 30°, 45°, 60° and 90°, and tangent at 0°, 30°, 45° and 60°.

Why is tan 90° undefined?

Because tan θ = sin θ ÷ cos θ and cos 90° is zero.

Do exact values need a calculator?

No. They are designed to be recalled or rebuilt from special triangles.

What does exact answer mean?

It means a fraction, integer, π-expression or surd rather than a rounded decimal approximation.

Build connected skills

What to revise next

Simplify roots

Surds

Calculate with and rationalise exact square-root expressions.

Revise surds
Content standards

Curriculum and rights review

Reviewed 5 September 2026 against DfE content G21 and current Pearson Edexcel, AQA and OCR GCSE Mathematics specifications. All questions and diagrams are original.